WebJan 20, 2014 · We have, S n = 4n 2 + n put n = 1, we get S 1 = 4(1) 2 + 1 = 4 + 1 = 5 So, First term, a 1 = 5 Put n = 2 , we get S 2 = 4(2) 2 + 2 = 18 so, a 2 = S 2 - S 1 = 18 - 5 = 13 Put n = 3, we get S 3 = 4(3) 2 + 3 = 39 a 3 = S 3 - S 2 = 39 - 18 = 21 So, the required AP is 5, 13, 21, ..... WebFeb 4, 2024 · Find the point on Y-axis which is equidistant from both points A(6,5) and B(−4,3) 9. Show that the points A(5,6),B(1,5),C(2,1) and D(6,2) are the vertices of a square. …
In an AP, if Sₙ = n(4n + 1), find the AP
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The sum of first n terms of an ap is 4 n2+2 n find the value of this ap
Web›H±•ÊªÐj¬ ~Üé;†S^0^ò¸`· È £ ÓëÝÅâ¦Y¾9 7Å` E7Ä ÷Ð ¦òa 8Å϶2Éu óé*žÚá+~6BØß þ‰Ä! ¥;QÏ®a R"YÛîò; Ý› ¯£Ñ Éú(® *ÿÁN™Ô²¼óÃÐG~ Å¿ÇV; 2ui\ªð¦ `‹™î7äÛèox¦sÕªU ÈmÄÙ6:Œv`ºÑf u··±–ƒf ßL¸Åðnö¯¼e—ÎÃN'V»rìý\Ý• V‡òÜ KMz ”ÎjŠ d ... WebFeb 5, 2024 · if the sum of n terms of an AP is given by Sn=n (4n+1),then find the nth term of the AP - Brainly.in 05.02.2024 Math Secondary School answered If the sum of n terms of an AP is given by Sn=n (4n+1),then find the nth term of the AP See answers Advertisement ideba2011 Answer:given below Step-by-step explanation: follow the steps..... Advertisement WebSep 20, 2024 · Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 … fishing licence ontario